Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 8 - Radical Functions - Chapter Test: 20

Answer

$6a\sqrt {5bc}$

Work Step by Step

$\sqrt {3ab}\times2\sqrt {15ac}$ =$2\times\sqrt {3ab}\times\sqrt {15ac}$ =$2\times\sqrt {3ab\times15ac}$ =$2\times\sqrt {9\times a^{2}\times5bc}$ =$2\times3a\sqrt {5bc}$ =$6a\sqrt {5bc}$
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