Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 8 - Radical Functions - Chapter Test - Page 672: 17

Answer

$266.67$ feet

Work Step by Step

Given \begin{equation} d=\sqrt{1.5 h}. \end{equation} We are given that $d=20$ miles and want to find how high, $h$, off the ground a person can see to the horizon. Set $d(h)=20$ and solve for $h$. \begin{equation} \begin{aligned} 20 & =\sqrt{1.5 h} \\ (20)^2 & =(\sqrt{1.5 h})^2 \\ 400& =1.5 h \\ \frac{400}{1.5} & =h \\ h&\approx 266.67. \end{aligned} \end{equation} A person's eyes have to be about $266.67$ feet off the ground to see $20$ miles to the horizon.
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