Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 8 - Radical Functions - 8.3 Multiplying and Dividing Radicals - 8.3 Exercises - Page 643: 90

Answer

$\frac{2\sqrt[3] {25g^2}}{75g}$.

Work Step by Step

The given expression is $=\frac{2\sqrt[3] {gh}}{15\sqrt[3]{5g^2h}}$ Use division rule. $=\frac{2}{15}\sqrt[3] {\frac{gh}{5g^2h}}$ Reduce the fraction. $=\frac{2}{15}\sqrt[3] {\frac{1}{5g}}$ Multiply by the needed factors. $=\frac{2}{15}\sqrt[3] {\frac{1}{5g}}\cdot \sqrt[3] {\frac{5^2g^2}{5^2g^2}}$ Use multiplication rule. $=\frac{2}{15}\sqrt[3] {\frac{5^2g^2}{5g\cdot 5^2g^2}}$ Simplify. $=\frac{2}{15}\sqrt[3] {\frac{5^2g^2}{ 5^3g^3}}$ Cube root the denominator. $=\frac{2\sqrt[3] {5^2g^2}}{15\cdot 5g}$ Simplify. $=\frac{2\sqrt[3] {25g^2}}{75g}$.
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