Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 8 - Radical Functions - 8.3 Multiplying and Dividing Radicals - 8.3 Exercises - Page 643: 85

Answer

$\frac{24-8\sqrt{5x}}{9-5x}$.

Work Step by Step

The given expression is $=\frac{8}{3+\sqrt{5x}}$ Multiply and divide by the conjugate of the denominator. $=\frac{8}{3+\sqrt{5x}}\cdot \frac{3-\sqrt{5x}}{3-\sqrt{5x}}$ Use distributive property and the FOIL method. $=\frac{24-8\sqrt{5x}}{9-3\sqrt{5x}+3\sqrt{5x}+(\sqrt{5x})(-\sqrt{5x})}$ Simplify. $=\frac{24-8\sqrt{5x}}{9-5x}$.
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