Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 8 - Radical Functions - 8.3 Multiplying and Dividing Radicals - 8.3 Exercises - Page 643: 69

Answer

$10-5\sqrt3$.

Work Step by Step

The given expression is $=\frac{5}{2+\sqrt3}$ Multiply and divide by the conjugate of the denominator. $=\frac{5}{2+\sqrt3}\cdot \frac{2-\sqrt3}{2-\sqrt3}$ Use distributive property and the FOIL method. $=\frac{10-5\sqrt3}{4+2\sqrt3-2\sqrt3+(\sqrt3)(-\sqrt3)}$ Simplify. $=\frac{10-5\sqrt3}{4-3}$ $=\frac{10-5\sqrt3}{1}$ $=10-5\sqrt3$.
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