Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 8 - Radical Functions - 8.3 Multiplying and Dividing Radicals - 8.3 Exercises - Page 643: 63

Answer

What Hung did wrong was that he did not multiply both the numerator and the denominator by the denominator. This would have kept the rational expression equivalent to the original rational expression. $4\sqrt {14}$

Work Step by Step

What Hung did wrong was that he did not multiply both the numerator and the denominator by the denominator. This would have kept the rational expression equivalent to the original rational expression. To simplify the expression, we can't leave radicals in the denominator, so to get rid of radicals in the denominator, we multiply both numerator and denominator by the denominator: $\frac{8\sqrt {7x}}{\sqrt {2x}} • \frac{\sqrt {2x}}{\sqrt {2x}}$ Multiply to simplify: $\frac{8\sqrt {14x^2}}{\sqrt {4x^2}}$ Take the square roots: $\frac{8 • x\sqrt {14}}{2x}$ Multiply coefficients: $\frac{8x\sqrt {14}}{2x}$ Cancel out factors that are common to both the numerator and denominator: $4\sqrt {14}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.