Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 8 - Radical Functions - 8.3 Multiplying and Dividing Radicals - 8.3 Exercises - Page 643: 72

Answer

$-\frac{28+20\sqrt3+7\sqrt5+ 5\sqrt{15}}{26}$.

Work Step by Step

The given expression is $=\frac{4+\sqrt5}{7-5\sqrt3}$ Multiply and divide by the conjugate of the denominator. $=\frac{4+\sqrt5}{7-5\sqrt3}\cdot \frac{7+5\sqrt3}{7+5\sqrt3}$ Use the FOIL method. $=\frac{28+20\sqrt3+7\sqrt5+\sqrt5\cdot 5\sqrt3}{49+35\sqrt3-35\sqrt3+(-5\sqrt3)(5\sqrt3)}$ Simplify. $=\frac{28+20\sqrt3+7\sqrt5+ 5\sqrt{15}}{49-75}$ $=\frac{28+20\sqrt3+7\sqrt5+ 5\sqrt{15}}{-26}$ $=-\frac{28+20\sqrt3+7\sqrt5+ 5\sqrt{15}}{26}$.
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