Answer
$28+4\sqrt 6+7\sqrt {2x}+3\sqrt {3x}$
Work Step by Step
$\sqrt {3x}+(4+\sqrt {2x})(7+\sqrt 6)$
=$\sqrt {3x}+[4(7+\sqrt 6)+\sqrt {2x}(7+\sqrt 6)]$
=$\sqrt {3x}+(28+4\sqrt 6+7\sqrt {2x}+\sqrt {6\times2x})$
=$\sqrt {3x}+28+4\sqrt 6+7\sqrt {2x}+\sqrt {12x}$
=$\sqrt {3x}+28+4\sqrt 6+7\sqrt {2x}+\sqrt {4\times3x}$
=$\sqrt {3x}+28+4\sqrt 6+7\sqrt {2x}+2\sqrt {3x}$
=$28+4\sqrt 6+7\sqrt {2x}+2\sqrt {3x}+\sqrt {3x}$
=$28+4\sqrt 6+7\sqrt {2x}+3\sqrt {3x}$
