## Intermediate Algebra: Connecting Concepts through Application

$\sqrt{-9}$ is not a real number because there is no real number that when squared gives $-9$.
Note that: $\sqrt{9} = 3$ because $3^2=9$ $\sqrt{16}=4$ because $4^2=16$ The given radical is NOT A REAL NUMBER because there is no real number that when squared gives $-9$.