## Intermediate Algebra: Connecting Concepts through Application

$\color{blue}{6xyz^2\sqrt[3]{18y^2z^2}}$
Factor the radicand so that at least one factor is a perfect cube: $=\sqrt[3]{216x^3y^3z^6(18y^2z^2)} \\=\sqrt[3]{6^3x^3y^3(z^2)^3(18y^2z^2)}$ Bring out the cube root of the perfect cube factors to obtain: $=\color{blue}{6xyz^2\sqrt[3]{18y^2z^2}}$