Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 8 - Radical Functions - 8.2 Simplifying, Adding, and Subtracting Radicals - 8.2 Exercises: 24

Answer

It can be seen that Shannon incorrectly took the square roots. Therefore, the correct answer is $2a^{2}\sqrt[3] {2b^{10}}$.

Work Step by Step

Step 1: We will solve the expression to find the correct answer and to determine Shannon's mistake. Step 2: $\sqrt[3] {16a^{6}b^{10}}$ Step 3: $\sqrt[3] {16}\times\sqrt[3] {a^{6}}\times\sqrt[3] {b^{10}}$ Step 4: $\sqrt[3] {2\times8}\times(a)^{6\times\frac{1}{3}}\times (b)^{10\times\frac{1}{3}}$ Step 5: $\sqrt[3] {2}\times\sqrt[3] 8\times(a)^{2}\times (b)^{\frac{10}{3}}$ Step 6: $\sqrt[3] {2}\times2\times a^{2}\times \sqrt[3] {b^{10}}$ Step 7: Therefore, the correct answer is $2a^{2}\sqrt[3] {2b^{10}}$ Step 8: It can be seen that Shannon incorrectly took the square roots.
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