Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 8 - Radical Functions - 8.2 Simplifying, Adding, and Subtracting Radicals - 8.2 Exercises: 7

Answer

$-2$

Work Step by Step

$\sqrt[3] {-8}=\sqrt[3] {(-2)^{3}}=(-2)^{3\times\frac{1}{3}}=-2$
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