Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 8 - Radical Functions - 8.2 Simplifying, Adding, and Subtracting Radicals - 8.2 Exercises: 2

Answer

$4$

Work Step by Step

Note that $16=4^2$. Thus, the given expression is equivalent to: $\sqrt{4^2}$ RECALL: For $a \ge0$, $\sqrt{a^2}=a$. Using the rule above gives: $\sqrt{4^2} = 4$
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