Intermediate Algebra: Connecting Concepts through Application

$\sqrt{-4}$ is not a real number because there is no real number that when squared gives $-4$.

Work Step by Step

Note that: $\sqrt{9} = 3$ because $3^2=9$ $\sqrt{16}=4$ because $4^2=16$ The given radical is NOT A REAL NUMBER because there is no real number that when squared gives $-4$.

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