Answer
$= \frac{1}{3} \log_7 3 + \log_7 x + \frac{4}{3} \log_7 y$
Work Step by Step
$= \log_7 (\sqrt[3] {3x^{3}y^{4}})$
$= \log_7 (3x^{3}y^{4})^{\frac{1}{3}}$
$= \frac{1}{3} \log_7 (3x^{3}y^{4})$
$= \frac{1}{3} \log_7 3 + \frac{1}{3} \log_7 x^{3} + \frac{1}{3} \log_7 y^{4}$
$= \frac{1}{3} \log_7 3 + \frac{3}{3} \log_7 x + \frac{4}{3} \log_7 y$
$= \frac{1}{3} \log_7 3 + \log_7 x + \frac{4}{3} \log_7 y$
