Answer
$= \log 2 + 2 \log x - \log y$
Work Step by Step
$ \log (\frac{2x^{2}}{y})$
$= \log 2x^{2} - \log y$
$= \log 2 + \log x^{2} - \log y$
$= \log 2 + 2 \log x - \log y$
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