Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 6 - Logarithmic Functions - 6.4 Properties of Logarithms - 6.4 Exercises: 24

Answer

$= \frac{1}{2} \log_9 7 + \frac{5}{2} \log_9 a + \frac{3}{2} \log_9 b$

Work Step by Step

$= \log_9 (\sqrt {7a^{5}b^{3}})$ $= \log_9 (7a^{5}b^{3})^{\frac{1}{2}}$ $= \frac{1}{2} \log_9 (7a^{5}b^{3})$ $= \frac{1}{2} \log_9 7 + \frac{1}{2} \log_9 a^{5} + \frac{1}{2} \log_9 b^{3}$ $= \frac{1}{2} \log_9 7 + \frac{5}{2} \log_9 a + \frac{3}{2} \log_9 b$
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