Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 6 - Logarithmic Functions - 6.4 Properties of Logarithms - 6.4 Exercises: 20

Answer

$= \frac{1}{2} \ln 6 + \frac{1}{2} \ln a$

Work Step by Step

$= \ln (\sqrt {6a})$ $= \ln (6a)^{\frac{1}{2}}$ $= \frac{1}{2} \ln 6a$ $= \frac{1}{2} \ln 6 + \frac{1}{2} \ln a$
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