Answer
$= \frac{1}{2} \ln 6 + \frac{1}{2} \ln a$
Work Step by Step
$= \ln (\sqrt {6a})$
$= \ln (6a)^{\frac{1}{2}}$
$= \frac{1}{2} \ln 6a$
$= \frac{1}{2} \ln 6 + \frac{1}{2} \ln a$
Intermediate Algebra: Connecting Concepts through Application
by Clark, Mark; Anfinson, Cynthia
Published by
Brooks Cole
ISBN 10:
0-53449-636-9
ISBN 13:
978-0-53449-636-4
Chapter 6 - Logarithmic Functions - 6.4 Properties of Logarithms - 6.4 Exercises - Page 516: 20
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