Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 4 - Quadratic Functions - 4.5 Solving Equations by Factoring - 4.5 Exercises - Page 362: 87



Work Step by Step

Divide $3$ on both sides: \begin{align*} \frac{3(h+5)}{3}&=\frac{22}{3}\\\\\ h+5&=\frac{22}{3}\\\\ h&=-5+\frac{22}{3}\\\\ h&=\frac{-15}{3}+\frac{22}{3}\\\\ h&=\frac{7}{3} \end{align*} Checking: \begin{align*} 3\left(\frac{7}{3}+5\right)&=22\\ 7+15&=22\\ 22&\stackrel{\checkmark}=22 \end{align*} Thus, the solution is $\dfrac{7}{3}$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.