Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 4 - Quadratic Functions - 4.5 Solving Equations by Factoring - 4.5 Exercises - Page 362: 83

Answer

The solution set is $\left\{-5, 5\right\}$.

Work Step by Step

Add $100$ to both sides: \begin{align*} 4x^2-100+100&=0+100\\ 4x^2&=100 \end{align*} Divide $4$ on both sides to obtain: $$x^2=25$$ Take the square root of both sides to obtain: \begin{align*} \sqrt{x^2}&=\pm\sqrt{25}\\ x&=\pm5 \end{align*} Thus, the solution set is $\left\{-5, 5\right\}$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.