Chapter 4 - Quadratic Functions - 4.2 Graphing Quadratics in Vertex Form - 4.2 Exercises - Page 317: 27

See graph

Given $$\begin{aligned} g(x) &= 4(x-5)^2. \end{aligned}$$ The vertex of the function is $(h,k)=(5,0)$. We determine the vertical intercept: $$g(0)=4(0-5)^2=100.$$ The vertical intercept is $(0,100)$. We use two pairs of symmetrical points: $(4,4)$, $(6,4)$ and $(0,100)$, $(10,100)$. The graph of the function is shown below.