Chapter 4 - Quadratic Functions - 4.2 Graphing Quadratics in Vertex Form - 4.2 Exercises - Page 317: 23

See graph

Given $$\begin{aligned} f(x) &= -1.5x^2. \end{aligned}$$ The vertex of the function is $(h,k)=(0,0)$. We determine the vertical intercept: $$f(0)=-1.5(0^2)=0.$$ The vertical intercept is $(0,0)$. We use two symmetrical points: $(-2,-6)$ and $(2,-6)$. The graph of the function is shown below.