Chapter 4 - Quadratic Functions - 4.2 Graphing Quadratics in Vertex Form - 4.2 Exercises - Page 317: 24

See graph

Given $$\begin{aligned} g(t) &= 0.5t^2. \end{aligned}$$ The vertex of the function is $(h,k)=(0,0)$. We determine the vertical intercept: $$g(0)=0.5(0^2)=0.$$ The vertical intercept is $(0,0)$. We use two symmetrical points: $(-2,2)$ and $(2,2)$. The graph of the function is shown below.