Answer
See graph
Work Step by Step
Given $$\begin{aligned}
f(x) &= (x-5)^2+ 3.
\end{aligned}$$ The vertex of t6he function is $(h,k)=(5,3)$.
We determine the vertical intercept: $$f(0)=(0-5)^2+3=28.$$ The vertical intercept is $(0,28)$.
We use two symmetrical points: $(3,7)$ and $(7,7)$.
The graph of the function is shown below
