Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 4 - Quadratic Functions - 4.2 Graphing Quadratics in Vertex Form - 4.2 Exercises - Page 317: 19

Answer

See graph

Work Step by Step

Using the vertex $(h,k)=(7,9)$, we write $$f(x)=a(x-7)^2+9.$$ To determine $a$ use the vertical intercept: $$\begin{aligned} f(0) &= 58\\ a(0-7)^2+ 9&=58\\ 49a& =49\\ a&=1. \end{aligned}$$ The function is completely determined: $$f(x)=(x-7)^2+9.$$ The graph of the function is shown below with the vertex at $ (7,9)$, vertical intercept at $(0,58)$ and an additional point of symmetry.
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