Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 1-6 - Cumulative Review - Page 549: 74


$= \frac{-81g^{12}}{h^{16}}$

Work Step by Step

$(-3g^{3}h^{-4})^{4}$ $= -81g^{12}h^{-16}$ $= \frac{-81g^{12}}{h^{16}}$
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