Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 1-6 - Cumulative Review - Page 549: 60

Answer

$= (2x+3)(x-7)$

Work Step by Step

$2x^{2} -11x -21$ 1. Find two numbers that can be multiplied together to obtain $(-21) \times 2 = -42$ and can be added to obtain $-11$. Numbers $-14$ and $3$. 2. Rewrite the equation using these two numbers $2x^{2} - 14x + 3x - 21$ $= 2x(x-7) + 3(x-7)$ $= (2x+3)(x-7)$
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