## Intermediate Algebra: Connecting Concepts through Application

$g^{-1}(x) = \log_3 \frac{x}{4}$
$g(x) = 4(3)^{x}$ Let $g(x) = y$ $y = 4(3)^{x}$ Swap $x$ and $y$ then solve for $y$ $x = 4(3)^{y}$ $\frac{x}{4} = (3)^{y}$ $y = \log_3 \frac{x}{4}$ $g^{-1}(x) = \log_3 \frac{x}{4}$