Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 1-6 - Cumulative Review: 70

Answer

$g^{-1}(x) = \log_3 \frac{x}{4}$

Work Step by Step

$g(x) = 4(3)^{x}$ Let $g(x) = y$ $y = 4(3)^{x}$ Swap $x$ and $y$ then solve for $y$ $x = 4(3)^{y}$ $\frac{x}{4} = (3)^{y}$ $y = \log_3 \frac{x}{4}$ $g^{-1}(x) = \log_3 \frac{x}{4}$
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