## Intermediate Algebra: Connecting Concepts through Application

$f^{-1}(x) = \frac{x-12}{3}$
$f(x) = 3x+12$ Let $f(x) = y$ $y = 3x+12$ Swap $x$ and $y$ and then solve for $y$. $x = 3y + 12$ $x-12 = 3y$ $y = \frac{x-12}{3}$ $f^{-1}(x) = \frac{x-12}{3}$