Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 1-6 - Cumulative Review - Page 549: 62

Answer

$7g(3g-8)(2g+5)$

Work Step by Step

First factor out the greatest common factor $7g$: $42g^3-7g^2-280g=7g(6g^2-g-40)$ Rewrite the middle term and group terms: $7g(6g^2-16g+15g-40)=7g[2g(3g-8)+5(3g-8)]$ Factor out $3g-8$ from each group: $7g(3g-8)(2g+5)$
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