Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Practice Final Exam - Page 705: 7

Answer

$\dfrac{8a^{\frac{1}{3}}c^{\frac{2}{3}}}{b^{\frac{5}{12}}}$

Work Step by Step

Using the laws of exponents, the given expression, $ \left( \dfrac{64c^{4/3}}{a^{-2/3}b^{5/6}} \right)^{1/2} ,$ simplifies to \begin{array}{l}\require{cancel} \dfrac{64^{\frac{1}{2}}c^{\frac{4}{3}\cdot\frac{1}{2}}}{a^{-\frac{2}{3}\cdot\frac{1}{2}}b^{\frac{5}{6}\cdot\frac{1}{2}}} \\\\= \dfrac{8c^{\frac{4}{6}}}{a^{-\frac{2}{6}}b^{\frac{5}{12}}} \\\\= \dfrac{8c^{\frac{2}{3}}}{a^{-\frac{1}{3}}b^{\frac{5}{12}}} \\\\= \dfrac{8a^{\frac{1}{3}}c^{\frac{2}{3}}}{b^{\frac{5}{12}}} .\end{array}
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.