Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Practice Final Exam - Page 705: 39

Answer

$\left(-4,\dfrac{7}{2} \right)$

Work Step by Step

Using $\left(\dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2} \right)$ or the Midpoint Formula, the midpoint of the line segment joining the given points $ (-2,-5) \text{ and } (-6,12) $ is \begin{array}{l}\require{cancel} \left(\dfrac{-2+(-6)}{2},\dfrac{-5+12}{2} \right) \\\\= \left(\dfrac{-2-6}{2},\dfrac{-5+12}{2} \right) \\\\= \left(\dfrac{-8}{2},\dfrac{7}{2} \right) \\\\= \left(-4,\dfrac{7}{2} \right) .\end{array}
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