Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Practice Final Exam - Page 705: 13

Answer

$2x^3-13x^2+14x-4$

Work Step by Step

Using the Distributive Property, the given expression, $ (2x-1)(x^2-6x+4) ,$ is equivalent to \begin{array}{l}\require{cancel} 2x(x^2)+2x(-6x)+2x(4)-1(x^2)-1(-6x)-1(4) \\\\= 2x^3-12x^2+8x-x^2+6x-4 \\\\= 2x^3+(-12x^2-x^2)+(8x+6x)-4 \\\\= 2x^3-13x^2+14x-4 .\end{array}
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