Answer
$x>-\frac{3}{2}$
Work Step by Step
$2x^2-7x>15$
$2x^2-7x-15>0$
$(2x+3)(x-5)>0$
$2x+3>0$
$x>-\frac{3}{2}$
$x-5>0$
$x>5$
$x>-\frac{3}{2}$
Intermediate Algebra (6th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321785045
ISBN 13:
978-0-32178-504-6
Practice Final Exam - Page 705: 28
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