Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Practice Final Exam - Page 705: 17

Answer

$-|x|\sqrt{5x}$

Work Step by Step

Using the laws of exponents, the given expression, $ \sqrt{125x^3}-3\sqrt{20x^3} ,$ simplifies to \begin{array}{l}\require{cancel} \sqrt{25x^2\cdot5x}-3\sqrt{4x^2\cdot5x} \\\\= \sqrt{(5x)^2\cdot5x}-3\sqrt{(2x)^2\cdot5x} \\\\= |5x|\sqrt{5x}-3\cdot|2x|\sqrt{5x} \\\\= 5|x|\sqrt{5x}-3\cdot2|x|\sqrt{5x} \\\\= 5|x|\sqrt{5x}-6|x|\sqrt{5x} \\\\= (5-6)|x|\sqrt{5x} \\\\= -|x|\sqrt{5x} .\end{array}
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