Answer
$\frac{3a^7}{2b^5}$
Work Step by Step
$\frac{6^{-1}a^2b^{-3}}{3^{-2}a^{-5}b^2}$
$\frac{9a^5a^2}{6b^3b^2}$
$\frac{3a^7}{2b^5}$
Intermediate Algebra (6th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321785045
ISBN 13:
978-0-32178-504-6
Practice Final Exam - Page 705: 6
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