Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Test - Page 471: 36

Answer

$\left( -\dfrac{1}{2},-\dfrac{3}{10} \right)$

Work Step by Step

Using $\left( \dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2} \right)$ or the Midpoint Formula, then the midpoint of the line segment joing the given points, $ \left( -\dfrac{2}{3},-\dfrac{1}{5} \right) \text{ and } \left( -\dfrac{1}{3},\dfrac{4}{5} \right) ,$ is \begin{array}{l}\require{cancel} \left( \dfrac{-\dfrac{2}{3}+\left(-\dfrac{1}{3}\right)}{2},\dfrac{-\dfrac{1}{5}+\dfrac{4}{5}}{2} \right) \\\\= \left( \dfrac{-\dfrac{2}{3}-\dfrac{1}{3}}{2},\dfrac{-\dfrac{1}{5}+\dfrac{4}{5}}{2} \right) \\\\= \left( \dfrac{-\dfrac{3}{3}}{2},\dfrac{-\dfrac{3}{5}}{2} \right) \\\\= \left( \dfrac{-1}{2},\dfrac{-3}{10} \right) \\\\= \left( -\dfrac{1}{2},-\dfrac{3}{10} \right) .\end{array}
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