Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Test - Page 471: 18

Answer

$\sqrt{6}+\sqrt{2}-4\sqrt{3}-4$

Work Step by Step

Using the properties of radicals, the given expression, $ (\sqrt{2}-4)(\sqrt{3}+1) ,$ simplifies to \begin{array}{l}\require{cancel} (\sqrt{2}-4)(\sqrt{3}+1) \\\\= \sqrt{2}(\sqrt{3})+\sqrt{2}(1)-4(\sqrt{3})-4(1) \\\\= \sqrt{2(3)}+\sqrt{2}-4\sqrt{3}-4 \\\\= \sqrt{6}+\sqrt{2}-4\sqrt{3}-4 .\end{array}
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