Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Test - Page 471: 35

Answer

$\left( -4,\dfrac{7}{2} \right)$

Work Step by Step

Using $\left( \dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2} \right)$ or the Midpoint Formula, then the midpoint of the line segment joing the given points, $ \left( -2,-5 \right) \text{ and } \left( -6,12 \right) ,$ is \begin{array}{l}\require{cancel} \left( \dfrac{-2+(-6)}{2},\dfrac{-5+12}{2} \right) \\\\= \left( \dfrac{-2-6}{2},\dfrac{-5+12}{2} \right) \\\\= \left( \dfrac{-8}{2},\dfrac{7}{2} \right) \\\\= \left( -4,\dfrac{7}{2} \right) .\end{array}
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