Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Test - Page 471: 26

Answer

$-2i\sqrt{2}$

Work Step by Step

Using $i=\sqrt{-1}$ and the properties of radicals, the given expression, $ -\sqrt{-8} ,$ simplifies to \begin{array}{l}\require{cancel} -\sqrt{-1}\cdot\sqrt{8} \\\\= -i\sqrt{4\cdot2} \\\\= -i\sqrt{(2)^2\cdot2} \\\\= -i\cdot2\sqrt{2} \\\\= -2i\sqrt{2} .\end{array}
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.