Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Test - Page 471: 24

Answer

$x=6$

Work Step by Step

Raising both sides to the third power of the given equation, $ \sqrt[3]{x+5}=\sqrt[3]{2x-1} ,$ then the solution/s is/are \begin{array}{l}\require{cancel} x+5=2x-1 \\\\ x-2x=-1-5 \\\\ -x=-6 \\\\ x=6 .\end{array}
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