Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Test - Page 471: 33

Answer

$d=2\sqrt{26}$

Work Step by Step

Using $d=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}$ (or the Distance Formula), then the distance, $d$, between the given points $ (-6,3) \text{ and } (-8,-7) ,$ is \begin{array}{l}\require{cancel} d=\sqrt{(-6-(-8))^2+(3-(-7))^2} \\\\ d=\sqrt{(-6+8)^2+(3+7)^2} \\\\ d=\sqrt{(2)^2+(10)^2} \\\\ d=\sqrt{4+100} \\\\ d=\sqrt{104} \\\\ d=\sqrt{4\cdot26} \\\\ d=\sqrt{(2)^2\cdot26} \\\\ d=2\sqrt{26} .\end{array}
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