Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 6 - Test - Page 406: 4

Answer

$\dfrac{x}{x+9}$

Work Step by Step

The given expression, $ \dfrac{x^2-4x}{x^2+5x-36} ,$ simplifies to \begin{array}{l}\require{cancel} \dfrac{x(x-4)}{(x+9)(x-4)} \\\\= \dfrac{x(\cancel{x-4})}{(x+9)(\cancel{x-4})} \\\\= \dfrac{x}{x+9} .\end{array}
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