Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 6 - Test - Page 406: 17

Answer

$\dfrac{4xy}{3z}+\dfrac{3x}{z}+y$

Work Step by Step

The given expression, $ (4x^2y+9x+3xyz)\div3xz ,$ simplifies to \begin{array}{l}\require{cancel} \dfrac{4x^2y}{3xz}+\dfrac{9x}{3xz}+\dfrac{3xyz}{3xz} \\\\= \dfrac{4xy}{3z}+\dfrac{3x}{z}+y .\end{array}
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