Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 6 - Test - Page 406: 15

Answer

$\dfrac{64}{3}$

Work Step by Step

The given expression, $ \dfrac{\dfrac{5}{x}-\dfrac{7}{3x}}{\dfrac{9}{8x}-\dfrac{1}{x}} ,$ simplifies to \begin{array}{l}\require{cancel} \dfrac{\dfrac{15-7}{3x}}{\dfrac{9-8}{8x}} \\\\= \dfrac{\dfrac{8}{3x}}{\dfrac{1}{8x}} \\\\= \dfrac{8}{3x}\div\dfrac{1}{8x} \\\\= \dfrac{8}{3x}\cdot8x \\\\= \dfrac{8}{3\cancel{x}}\cdot8\cancel{x} \\\\= \dfrac{64}{3} .\end{array}
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