Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 6 - Test - Page 406: 21



Work Step by Step

By cross-multiplication, the solution to the given equation, $ \dfrac{5x+3}{3x-7}=\dfrac{19}{7} ,$ is equivalent to \begin{array}{l}\require{cancel} 7(5x+3)=19(3x-7) \\\\ 35x+21=57x-133 \\\\ 35x-57x=-133-21 \\\\ -22x=-154 \\\\ x=\dfrac{-154}{-22} \\\\ x=7 .\end{array}
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