Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 6 - Test - Page 406: 19

Answer

$4x^3-15x^2+45x-136+\dfrac{407}{x+3}$

Work Step by Step

Using the long division method below, then \begin{array}{l}\require{cancel} ( 4x^4-3x^3-x-1 )\div( x+3 ) \\= 4x^3-15x^2+45x-136+\dfrac{407}{x+3} .\end{array}
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