Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 6 - Test - Page 406: 22



Work Step by Step

Multiplying both sides by the $LCD= x-4 ,$ then the solution to the given equation, $ \dfrac{x}{x-4}=3-\dfrac{4}{x-4} ,$ is \begin{array}{l}\require{cancel} 1(x)=(x-4)(3)-1(4) \\\\ x=3x-12-4 \\\\ x-3x=-12-4 \\\\ -2x=-16 \\\\ x=\dfrac{-16}{-2} \\\\ x=8 .\end{array}
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