Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Review - Page 331: 139


$$x=-\frac{15}{2}$$ $$x=7$$

Work Step by Step

Let $x$ be the number $$x+2x^2=105$$ $$2x^2+x-105=0$$ $$(2x+15)(x-7)=0$$ Solving each parenthesis 1)$$2x+15=0$$ $$x=-\frac{15}{2}$$ 2)$$x-7=0$$ $$x=7$$
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