## Intermediate Algebra (6th Edition)

$$x=2$$ $$x=10$$
We have $$2x(x-12)=-40$$ Solving the equation $$2x^2-24x+40=0$$ Factorizing $$(2x-4)(x-10)=0$$ Solving each parenthesis (1)$$2x-4=0$$ $$2x=4$$ $$x=2$$ (2)$$x-10=0$$ $$x=10$$